x^2(x^2+1)=10(3x^2-10)

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Solution for x^2(x^2+1)=10(3x^2-10) equation: 



x^2(x^2+1)=10(3x^2-10)

We move all terms to the left:

x^2(x^2+1)-(10(3x^2-10))=0



We calculate terms in parentheses: -(10(3x^2-10)), so:

10(3x^2-10)

We multiply parentheses

30x^2-100

Back to the equation:

-(30x^2-100)



We get rid of parentheses

x^2(x^2+1)-30x^2+100=0

We add all the numbers together, and all the variables

-30x^2+x^2(x^2+1)+100=0

We move all terms containing x to the left, all other terms to the right

-30x^2+x^2(x^2+1)=-100

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